Q. T^T
f(x) = 4x + x!! × x
f(6) = ?
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f(x) = 4x + x!! × x
f(6) = ?
Jawaban:
[tex] \\ [/tex]
Diketahui :
- f(x) = 4x + x!! × x
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Ditanya :
- f(6) = ..?
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Dijawab :
- f(x) = 4x + x!! × x
- f(6) = 4(6) + 6!! × 6
- f(6) = ( 6 + 6 + 6 + 6 ) + 6!! × 6
- f(6) = ( 12 + 12 ) + 6!! × 6
- f(6) = 24 + 6!! × 6
- f(6) = 24 + ( 6 × 4 × 2 ) × 6
- f(6) = 24 + (24 × 2) × 6
- f(6) = 24 + ( 48 × 6 )
- f(6) = 24 + 288
- [tex]\tt\red{{{f(6) =}}}[/tex] [tex]\sf\underline \color{red}\boxed{312}[/tex]
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[tex] \\ [/tex]
Kesimpulan :
- maka nilai dari [tex]\tt\red{{{f(6)}}}[/tex] adalah [tex]\sf\underline \color{red}\boxed{312}[/tex]
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[tex] \\ [/tex]
Detail jawaban :
- Mapel : Matematika
- Kelas : Vlll ( SMP )
- Tingkat : Sekolah Menengah Pertama
- Materi : Fungsi
- Kode soal : 2
- Kode katagorisasi : 8.2.2
- Kata kunci : nilai dari [tex]\tt\red{{{f(6)}}}[/tex]
[tex] \\ [/tex]
- P ࿐ྂ
f(x) = 4x + x!! × x
f(6) = 4(6) + 6!! × 6
f(6) = 24 + (6 × 4 × 2) × 6
f(6) = 24 + (24 × 2) × 6
f(6) = 24 + 48 × 6
f(6) = 24 + 288
f(6) = 312
Ninmy!
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